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F(x y)=x^2+y^2- · It depends on whether we need d/dx or d/dt For d/dt d/dt(ln(x^2y^2)) = 1/(x^2y^2) d/dt(x^2y^2) = 1/(x^2y^2) * (2xdx/dt 2y dy/dt) For d/dx d/dx(ln(x^2y^2)) = 1/(x^2y^2) d/dx(x^2y^2) = 1/(x^2y^2) * (2x 2y dy/dx) Calculus Science Anatomy & Physiology AstronomySee the answer Show transcribed image text Expert Answer 100% (1 rating) Previous question Next question Transcribed Image Text from this Question f(x, y) = x^2 y^2 The constant is xy = 1 Find the max/min f(x, y




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Multivariable Calculus Sketch the contour map of f(x,y) = 1/(x^2 y^2) Label the level curves at c= 0, 1, 1/4, 4 We sketch the graph in three space toConsider the function ,(z,y)メ(0,0) , (z, y) = (0,0) f(z,y) = r,y)= 耳ア x2 y2 (i) Determine if f(x, y) is continuous at (0,0) (i) Explain briefly if f is differentiable at (0,0) (iii) Find (00) and fs(0,0), if they exist (iv) Find (z, y) and fs(x,y) when (z,y)メ(0,0) 3 Let z = er cos θ, r = st, θVs2t2 Find z8 and zt 4 Let f(z, y) 2 sin(zy) (i) Find the directions in whichClick here👆to get an answer to your question ️ If u = f(r) , where r^2 = x^2 y^2 then ( ∂^2u∂x^2 ∂^2u∂y^2 ) =
Find the work done by the force F = (x^2 y^2)i (x^2 y^2)j on an object traveling around the closed path bounded by y = 2 x^2 and y = 1 as shown Find the work done by the force F = (x^2y^2)i (4xy^3)j on an object traveling around the closed path bounded by y = 3x, y = 3 and the yF(x,y)=(x^2y^2)/x = 0 Learn more about 3d plots, homeworkBut avoid Asking for help, clarification, or responding to other answers
If u = lo g (x 2 y 2 z 2), then check whether following is true x = ∂ y ∂ z ∂ 2 u = y = ∂ z ∂ x ∂ 2 u = z = ∂ x ∂ z ∂ 2 u View solution If x = r c o s θ, y = r s i n θ, show that δ (r, θ) δ (x, y) = r View solution View more Learn with content Watch learning videos, swipe through stories, and browse through concepts Concepts > Videos > Stories > Classes Class · Because f(x,y)=sqrt(9x^2y^2) we must have that 9x^2y^2>=0=>9>=x^2y^2=>3^2>=x^2y^2 The domain of f(x,y) is the border and the interior of the circle x^2y^2=3^2 or The domain is represented by the disc whose center is the origin of the coordinates system and the radius is 3 Now hence f(x,y)>=0 and f(x,y)Multivariable Calculus Find the linear approximation to the function f(x, y) = x^2 y^2 x at the point (2, 3) Then approximate (21)^2 (29)^2 21For




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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge and · f_x = 2y * e^(x^2y^2) 2xy * 2xe^(x^2y^2)= y(2 4x^2) e^(x^2y^2) Similarly, f_y = x(2 4y^2) e^(x^2y^2) Now, we set these equal to 0 y(2 4x^2) = 0 and x(2 4y^2) = 0 (since exp is nonzero) If y = 0, then we have x = 0 Otherwise, 2 4x^2 = 0 ==> x = ±1/√2, and for each value of x, we find that y = ±1/√2Answer to For f(x, y) = sin (x^2 y^2), find all second derivative order partial derivatives, and verify that f_{xy} = f_{yx} By signing up,




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Domain of f(x,y) = log(1(x^2y^2)) Extended Keyboard;Indefinite integral assuming all variables are real Download Page POWERED BY THE WOLFRAM · Find fx(x, y) f(x, y) = (x^2 y^2) / xy Yahoo Answers is shutting down on May 4th, 21 (Eastern Time) and the Yahoo Answers website is now in readonly mode



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Question F(x, Y) = X^2 Y^2 The Constant Is Xy = 1 Find The Max/min F(x, Y, Z) = 2x 2y Z The Constant Is X^2 Y^2 Z^2 = 9 Find The Max/min This problem has been solved!Question Graph F(x Y)=sqrt(9x^2y^2) This problem has been solved!See the answer graph f(x y)=sqrt(9x^2y^2) Expert Answer 100% (1 rating) Previous question Next question Get more help from Chegg Solve it with our calculus problem solver and calculator



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· Homework Statement I have got a question concerning the following function f(x,y)=\log\left(x^2y^2\right) Partial derivatives are Insights Blog Browse All Articles Physics Articles Physics Tutorials Physics Guides Physics FAQ Math Articles Math Tutorials Math Guides Math FAQ Education Articles Education Guides Bio/Chem Articles Technology Guides ComputerContour plot Alternate form assuming x and y are real Alternate form Properties as a function Domain Range Parity Partial derivatives Stepbystep solution;Now to find the partial derivatives at (0,0) you have \lim_{x \to 0}\frac{f(x,0) f(0,0)}{x} = \lim_{x \to 0} \frac{\frac{x^2 0^2}{x^2 y^2} 0}{x} = \lim_{x \to 0} \frac 1x = \infty Obviously the partial derivatives exist at (x, y) = (0, 0), as it's a rational function and the denominator is never zero Now to find the partial derivatives at (0, 0) you have lim x → 0 x f (x, 0) �




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Thanks for contributing an answer to Mathematics Stack Exchange!{eq}f(x, y) = x^2 y e^{x^2 y^2} {/eq} Critical Point The critical point of the function consisting of two variables is evaluated using partial differentiation method First of all, the partial · I want to visualize the Lagrange Multiplier for f(x, y) = x^2 * y, with x, y lie on the circle around the origin with radius is square root of 3, g(x, y) = x^2 y^2 3 So I can plot the f function but it is too large and the circle is too small Do you know how to scale or resize it like this image?



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Let {eq}f(x,y,z)=x^2y^2z^2 {/eq} and let S be the level surface defined by f(x,y,z) = 4 (a) Find an equation for the plane tangent to S at {eq}P_{0}(1,1,2) {/eq} (b) While S is not the · What are the extrema and saddle points of #f(x,y) = x^2xyy^2y#?Prove that the function $\sqrt{x^2y^2}\sin \frac{1}{\sqrt{x^2y^2}}$ is uniformly continuous in $\mathbb R^2$ 1 prove $\frac{f(x)}{x}$ is uniformly continuous in $1,\infty$




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· For (1/sqrt2,1/sqrt2) it is easily seen that (del^2 f)/(del x^2) = (del^2 f)/(del y^2) = 2e^{1/2} · Here, F(r) = \text{arcsin}(r^22) First, you study the curve of equation z = \text{arcsin}(x^22) you get Second, you rotate this curve around (0z) axis and you get the surface S Remark that f exists only on the domain defined by 1\leq x^2y^2\leq 3 it's a disk of radius sqrt{3} with an circular hole of radius 1Stack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange




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This question currently has 12 answers, none of which, I'm afraid, are entirely correct or complete The question isn't clearly stated, either The question should likely be one of the following 1 Find all functions mathf\R\to\R/math such tThe points (x,y,z) of the sphere x 2 y 2 z 2 = 1, satisfying the condition x = 05, are a circle y 2 z 2 = 075 of radius on the plane x = 05 The inequality y ≤ 075 holds on an arc The length of the arc is 5/6 of the length of the circle, which is why the conditional probability is equal to 5/6 This successful geometric explanation may create the illusion that the followingCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge and




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On f(x 2 y 2) = f(x) 2 f(y) 2 Consider an integervalued function f(k) such that f(1) is positive and We can show that the only such function is the identity function f(k) = k To prove this, first note that setting m = 1 and n = 0 in equation (1) and rearranging terms gives the condition Since the integer f(1) is positive, and the square integer f(0) 2 must be nonnegative, itCalculus Graphing with the First Derivative Identifying Turning Points (Local Extrema) for a Function 1 Answer TruongSon N Dec 28, 16 I found no saddle points, but there was a minimum #f(1/3,2/3) = 1/3# To find the extrema, take the partial derivative with respect to #x# and #y# to see ifGet the free "Surface plot of f(x, y)" widget for your website, blog, Wordpress, Blogger, or iGoogle Find more Engineering widgets in WolframAlpha




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